======== Managers ======== .. currentmodule:: django.db.models .. class:: Manager() A ``Manager`` is the interface through which database query operations are provided to Django models. At least one ``Manager`` exists for every model in a Django application. The way ``Manager`` classes work is documented in :doc:`/topics/db/queries`; this document specifically touches on model options that customize ``Manager`` behavior. .. _manager-names: Manager names ============= By default, Django adds a ``Manager`` with the name ``objects`` to every Django model class. However, if you want to use ``objects`` as a field name, or if you want to use a name other than ``objects`` for the ``Manager``, you can rename it on a per-model basis. To rename the ``Manager`` for a given class, define a class attribute of type ``models.Manager()`` on that model. For example:: from django.db import models class Person(models.Model): #... people = models.Manager() Using this example model, ``Person.objects`` will generate an ``AttributeError`` exception, but ``Person.people.all()`` will provide a list of all ``Person`` objects. .. _custom-managers: Custom Managers =============== You can use a custom ``Manager`` in a particular model by extending the base ``Manager`` class and instantiating your custom ``Manager`` in your model. There are two reasons you might want to customize a ``Manager``: to add extra ``Manager`` methods, and/or to modify the initial ``QuerySet`` the ``Manager`` returns. Adding extra Manager methods ---------------------------- Adding extra ``Manager`` methods is the preferred way to add "table-level" functionality to your models. (For "row-level" functionality -- i.e., functions that act on a single instance of a model object -- use :ref:`Model methods `, not custom ``Manager`` methods.) A custom ``Manager`` method can return anything you want. It doesn't have to return a ``QuerySet``. For example, this custom ``Manager`` offers a method ``with_counts()``, which returns a list of all ``OpinionPoll`` objects, each with an extra ``num_responses`` attribute that is the result of an aggregate query:: from django.db import models class PollManager(models.Manager): def with_counts(self): from django.db import connection cursor = connection.cursor() cursor.execute(""" SELECT p.id, p.question, p.poll_date, COUNT(*) FROM polls_opinionpoll p, polls_response r WHERE p.id = r.poll_id GROUP BY p.id, p.question, p.poll_date ORDER BY p.poll_date DESC""") result_list = [] for row in cursor.fetchall(): p = self.model(id=row[0], question=row[1], poll_date=row[2]) p.num_responses = row[3] result_list.append(p) return result_list class OpinionPoll(models.Model): question = models.CharField(max_length=200) poll_date = models.DateField() objects = PollManager() class Response(models.Model): poll = models.ForeignKey(OpinionPoll) person_name = models.CharField(max_length=50) response = models.TextField() With this example, you'd use ``OpinionPoll.objects.with_counts()`` to return that list of ``OpinionPoll`` objects with ``num_responses`` attributes. Another thing to note about this example is that ``Manager`` methods can access ``self.model`` to get the model class to which they're attached. Modifying initial Manager QuerySets ----------------------------------- A ``Manager``’s base ``QuerySet`` returns all objects in the system. For example, using this model:: from django.db import models class Book(models.Model): title = models.CharField(max_length=100) author = models.CharField(max_length=50) ...the statement ``Book.objects.all()`` will return all books in the database. You can override a ``Manager``’s base ``QuerySet`` by overriding the ``Manager.get_queryset()`` method. ``get_queryset()`` should return a ``QuerySet`` with the properties you require. For example, the following model has *two* ``Manager``\s -- one that returns all objects, and one that returns only the books by Roald Dahl:: # First, define the Manager subclass. class DahlBookManager(models.Manager): def get_queryset(self): return super(DahlBookManager, self).get_queryset().filter(author='Roald Dahl') # Then hook it into the Book model explicitly. class Book(models.Model): title = models.CharField(max_length=100) author = models.CharField(max_length=50) objects = models.Manager() # The default manager. dahl_objects = DahlBookManager() # The Dahl-specific manager. With this sample model, ``Book.objects.all()`` will return all books in the database, but ``Book.dahl_objects.all()`` will only return the ones written by Roald Dahl. Of course, because ``get_queryset()`` returns a ``QuerySet`` object, you can use ``filter()``, ``exclude()`` and all the other ``QuerySet`` methods on it. So these statements are all legal:: Book.dahl_objects.all() Book.dahl_objects.filter(title='Matilda') Book.dahl_objects.count() This example also pointed out another interesting technique: using multiple managers on the same model. You can attach as many ``Manager()`` instances to a model as you'd like. This is an easy way to define common "filters" for your models. For example:: class AuthorManager(models.Manager): def get_queryset(self): return super(AuthorManager, self).get_queryset().filter(role='A') class EditorManager(models.Manager): def get_queryset(self): return super(EditorManager, self).get_queryset().filter(role='E') class Person(models.Model): first_name = models.CharField(max_length=50) last_name = models.CharField(max_length=50) role = models.CharField(max_length=1, choices=(('A', _('Author')), ('E', _('Editor')))) people = models.Manager() authors = AuthorManager() editors = EditorManager() This example allows you to request ``Person.authors.all()``, ``Person.editors.all()``, and ``Person.people.all()``, yielding predictable results. .. _default-managers: Default managers ~~~~~~~~~~~~~~~~ If you use custom ``Manager`` objects, take note that the first ``Manager`` Django encounters (in the order in which they're defined in the model) has a special status. Django interprets the first ``Manager`` defined in a class as the "default" ``Manager``, and several parts of Django (including :djadmin:`dumpdata`) will use that ``Manager`` exclusively for that model. As a result, it's a good idea to be careful in your choice of default manager in order to avoid a situation where overriding ``get_queryset()`` results in an inability to retrieve objects you'd like to work with. .. _managers-for-related-objects: Using managers for related object access ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ By default, Django uses an instance of a "plain" manager class when accessing related objects (i.e. ``choice.poll``), not the default manager on the related object. This is because Django needs to be able to retrieve the related object, even if it would otherwise be filtered out (and hence be inaccessible) by the default manager. If the normal plain manager class (:class:`django.db.models.Manager`) is not appropriate for your circumstances, you can force Django to use the same class as the default manager for your model by setting the ``use_for_related_fields`` attribute on the manager class. This is documented fully below_. .. _below: manager-types_ .. _calling-custom-queryset-methods-from-manager: Calling custom ``QuerySet`` methods from the ``Manager`` -------------------------------------------------------- While most methods from the standard ``QuerySet`` are accessible directly from the ``Manager``, this is only the case for the extra methods defined on a custom ``QuerySet`` if you also implement them on the ``Manager``:: class PersonQuerySet(models.QuerySet): def authors(self): return self.filter(role='A') def editors(self): return self.filter(role='E') class PersonManager(models.Manager): def get_queryset(self): return PersonQuerySet(self.model, using=self._db) def authors(self): return self.get_queryset().authors() def editors(self): return self.get_queryset().editors() class Person(models.Model): first_name = models.CharField(max_length=50) last_name = models.CharField(max_length=50) role = models.CharField(max_length=1, choices=(('A', _('Author')), ('E', _('Editor')))) people = PersonManager() This example allows you to call both ``authors()`` and ``editors()`` directly from the manager ``Person.people``. .. _create-manager-with-queryset-methods: Creating ``Manager`` with ``QuerySet`` methods ---------------------------------------------- In lieu of the above approach which requires duplicating methods on both the ``QuerySet`` and the ``Manager``, :meth:`QuerySet.as_manager() ` can be used to create an instance of ``Manager`` with a copy of a custom ``QuerySet``’s methods:: class Person(models.Model): ... people = PersonQuerySet.as_manager() The ``Manager`` instance created by :meth:`QuerySet.as_manager() ` will be virtually identical to the ``PersonManager`` from the previous example. Not every ``QuerySet`` method makes sense at the ``Manager`` level; for instance we intentionally prevent the :meth:`QuerySet.delete() ` method from being copied onto the ``Manager`` class. Methods are copied according to the following rules: - Public methods are copied by default. - Private methods (starting with an underscore) are not copied by default. - Methods with a ``queryset_only`` attribute set to ``False`` are always copied. - Methods with a ``queryset_only`` attribute set to ``True`` are never copied. For example:: class CustomQuerySet(models.QuerySet): # Available on both Manager and QuerySet. def public_method(self): return # Available only on QuerySet. def _private_method(self): return # Available only on QuerySet. def opted_out_public_method(self): return opted_out_public_method.queryset_only = True # Available on both Manager and QuerySet. def _opted_in_private_method(self): return _opted_in_private_method.queryset_only = False from_queryset ~~~~~~~~~~~~~ .. classmethod:: from_queryset(queryset_class) For advanced usage you might want both a custom ``Manager`` and a custom ``QuerySet``. You can do that by calling ``Manager.from_queryset()`` which returns a *subclass* of your base ``Manager`` with a copy of the custom ``QuerySet`` methods:: class BaseManager(models.Manager): def manager_only_method(self): return class CustomQuerySet(models.QuerySet): def manager_and_queryset_method(self): return class MyModel(models.Model): objects = BaseManager.from_queryset(CustomQueryset)() You may also store the generated class into a variable:: CustomManager = BaseManager.from_queryset(CustomQueryset) class MyModel(models.Model): objects = CustomManager() .. _custom-managers-and-inheritance: Custom managers and model inheritance ------------------------------------- Class inheritance and model managers aren't quite a perfect match for each other. Managers are often specific to the classes they are defined on and inheriting them in subclasses isn't necessarily a good idea. Also, because the first manager declared is the *default manager*, it is important to allow that to be controlled. So here's how Django handles custom managers and :ref:`model inheritance `: 1. Managers defined on non-abstract base classes are *not* inherited by child classes. If you want to reuse a manager from a non-abstract base, redeclare it explicitly on the child class. These sorts of managers are likely to be fairly specific to the class they are defined on, so inheriting them can often lead to unexpected results (particularly as far as the default manager goes). Therefore, they aren't passed onto child classes. 2. Managers from abstract base classes are always inherited by the child class, using Python's normal name resolution order (names on the child class override all others; then come names on the first parent class, and so on). Abstract base classes are designed to capture information and behavior that is common to their child classes. Defining common managers is an appropriate part of this common information. 3. The default manager on a class is either the first manager declared on the class, if that exists, or the default manager of the first abstract base class in the parent hierarchy, if that exists. If no default manager is explicitly declared, Django's normal default manager is used. These rules provide the necessary flexibility if you want to install a collection of custom managers on a group of models, via an abstract base class, but still customize the default manager. For example, suppose you have this base class:: class AbstractBase(models.Model): # ... objects = CustomManager() class Meta: abstract = True If you use this directly in a subclass, ``objects`` will be the default manager if you declare no managers in the base class:: class ChildA(AbstractBase): # ... # This class has CustomManager as the default manager. pass If you want to inherit from ``AbstractBase``, but provide a different default manager, you can provide the default manager on the child class:: class ChildB(AbstractBase): # ... # An explicit default manager. default_manager = OtherManager() Here, ``default_manager`` is the default. The ``objects`` manager is still available, since it's inherited. It just isn't used as the default. Finally for this example, suppose you want to add extra managers to the child class, but still use the default from ``AbstractBase``. You can't add the new manager directly in the child class, as that would override the default and you would have to also explicitly include all the managers from the abstract base class. The solution is to put the extra managers in another base class and introduce it into the inheritance hierarchy *after* the defaults:: class ExtraManager(models.Model): extra_manager = OtherManager() class Meta: abstract = True class ChildC(AbstractBase, ExtraManager): # ... # Default manager is CustomManager, but OtherManager is # also available via the "extra_manager" attribute. pass Note that while you can *define* a custom manager on the abstract model, you can't *invoke* any methods using the abstract model. That is:: ClassA.objects.do_something() is legal, but:: AbstractBase.objects.do_something() will raise an exception. This is because managers are intended to encapsulate logic for managing collections of objects. Since you can't have a collection of abstract objects, it doesn't make sense to be managing them. If you have functionality that applies to the abstract model, you should put that functionality in a ``staticmethod`` or ``classmethod`` on the abstract model. Implementation concerns ----------------------- Whatever features you add to your custom ``Manager``, it must be possible to make a shallow copy of a ``Manager`` instance; i.e., the following code must work:: >>> import copy >>> manager = MyManager() >>> my_copy = copy.copy(manager) Django makes shallow copies of manager objects during certain queries; if your Manager cannot be copied, those queries will fail. This won't be an issue for most custom managers. If you are just adding simple methods to your ``Manager``, it is unlikely that you will inadvertently make instances of your ``Manager`` uncopyable. However, if you're overriding ``__getattr__`` or some other private method of your ``Manager`` object that controls object state, you should ensure that you don't affect the ability of your ``Manager`` to be copied. .. _manager-types: Controlling automatic Manager types =================================== This document has already mentioned a couple of places where Django creates a manager class for you: `default managers`_ and the "plain" manager used to `access related objects`_. There are other places in the implementation of Django where temporary plain managers are needed. Those automatically created managers will normally be instances of the :class:`django.db.models.Manager` class. .. _default managers: manager-names_ .. _access related objects: managers-for-related-objects_ Throughout this section, we will use the term "automatic manager" to mean a manager that Django creates for you -- either as a default manager on a model with no managers, or to use temporarily when accessing related objects. Sometimes this default class won't be the right choice. One example is in the :mod:`django.contrib.gis` application that ships with Django itself. All ``gis`` models must use a special manager class (:class:`~django.contrib.gis.db.models.GeoManager`) because they need a special queryset (:class:`~django.contrib.gis.db.models.GeoQuerySet`) to be used for interacting with the database. It turns out that models which require a special manager like this need to use the same manager class wherever an automatic manager is created. Django provides a way for custom manager developers to say that their manager class should be used for automatic managers whenever it is the default manager on a model. This is done by setting the ``use_for_related_fields`` attribute on the manager class:: class MyManager(models.Manager): use_for_related_fields = True # ... If this attribute is set on the *default* manager for a model (only the default manager is considered in these situations), Django will use that class whenever it needs to automatically create a manager for the class. Otherwise, it will use :class:`django.db.models.Manager`. .. admonition:: Historical Note Given the purpose for which it's used, the name of this attribute (``use_for_related_fields``) might seem a little odd. Originally, the attribute only controlled the type of manager used for related field access, which is where the name came from. As it became clear the concept was more broadly useful, the name hasn't been changed. This is primarily so that existing code will :doc:`continue to work ` in future Django versions. Writing correct Managers for use in automatic Manager instances --------------------------------------------------------------- As already suggested by the :mod:`django.contrib.gis` example, above, the ``use_for_related_fields`` feature is primarily for managers that need to return a custom ``QuerySet`` subclass. In providing this functionality in your manager, there are a couple of things to remember. Do not filter away any results in this type of manager subclass ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ One reason an automatic manager is used is to access objects that are related to from some other model. In those situations, Django has to be able to see all the objects for the model it is fetching, so that *anything* which is referred to can be retrieved. If you override the ``get_queryset()`` method and filter out any rows, Django will return incorrect results. Don't do that. A manager that filters results in ``get_queryset()`` is not appropriate for use as an automatic manager. Set ``use_for_related_fields`` when you define the class ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ The ``use_for_related_fields`` attribute must be set on the manager *class*, not on an *instance* of the class. The earlier example shows the correct way to set it, whereas the following will not work:: # BAD: Incorrect code class MyManager(models.Manager): # ... pass # Sets the attribute on an instance of MyManager. Django will # ignore this setting. mgr = MyManager() mgr.use_for_related_fields = True class MyModel(models.Model): # ... objects = mgr # End of incorrect code. You also shouldn't change the attribute on the class object after it has been used in a model, since the attribute's value is processed when the model class is created and not subsequently reread. Set the attribute on the manager class when it is first defined, as in the initial example of this section and everything will work smoothly.